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Category > Physics Posted 08 May 2017 My Price 4.00

alpha decay,

Suppose some nucleus undergoes alpha decay, releasing 5.7 MeV of energy. If the daughter product of this reaction is 93X237 (atomic mass = 237.04816) , it will recoil away as the alpha particle leaves. Determine (a) the energy of the daughter product and (b) the energy of the alpha particle (atomic mass = 4.002603 u). Assume that the energy of each particle is kinetic energy, and ignore any other small amounts of energy that might be carried away by other emissions. In addition, ignore relativistic effects.

 

I found the energy of the alpha particle to be equal to 5.69 MeV, and I thought from there I could just do 5.7-5.69 to get the answer for the daughter product, but that did not work. HELP find the answer to part A please!!!

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SuperTutor
(15)
Status NEW Posted 08 May 2017 03:05 AM My Price 4.00

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