Time of day
Midnight to 3AM Observed- Acidents
38 Expected- Acidents P(Expected)
0.05 3AM - 6AM 29 0.05 6AM - 9AM 66 0.1 9AM - Noon 77 0.1 Noon - 3PM 99 0.15 3PM - 6PM 127 0.15 6PM - 9PM 166 0.2 9PM - Midnight
Total 113
715 0 0.2
1.00 Problem: Suppose a safety officer proposes that bicycle
accidents will occur with the following distributions:
Midnight - 3AM = .05
3AM - 6AM = .05
6AM - 9AM = .10
9AM - Noon = .10
Noon - 3PM = .15
3PM - 6PM = .15
6PM - 9PM = .20
9PM - Midnight = .20
Test that the observed values equal the expected
distribution @ alpha = .05 level Chi-Square Evaluation Ho:
Ha: Observed Expected Sum of the Squared
Differences (O-E)^2 38 1444 29 841 66 4356 77 5929 99 9801 127 16129 166 27556 113
715 12769
78825 0 Goodness of Fit
[(O-E)^2] / E Chi- Square Value Chi-Square Test Statistic
=CHIINV(Alpha,D.F) p-Value
=CHIDIST(Chi-Square Value,D.F) State Results here:

• 1503385674-Chi_Square - Assignment 6 Template.pdf

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