A fast food company in a particular city has developed an improved process for serving drivethru customers during the noon-to-1:00 p.m. lunch period. The waiting time (defined as the time
the customer enters the drive-thru line until he or she receives their food) of 20 randomly
selected cars during this hour is recorded. The data are saved in a file called “Time.csv” which
can be found under the
In a separate word file, answer the following questions using complete sentences when
applicable and copying and pasting the relevant charts, tables and graphs when appropriate.
1.Using StatCrunch, create a histogram of the data with summary statistics. Report the values of
the sample mean and the sample standard deviation for these data. In addition, identify the
population and parameter of interest. Print histogram with summary statistics. Summary statistics: Column n Mean Std. dev.
Waiting Time 20 4.7091.5615913
The Population is all drive-thru customers were served during the noon-to-1:00 p.m The sample is the 20 randomly selected cars during the noon-to-1:00 p.m
The Parameter is the waiting time of all drive-thru customers were served during the noon-to-1:00 p.m
The Statistic is the average waiting time of the 20 randomly selected cars during the noon-to-1:00 p.m 2. Using StatCrunch, construct a 90% confidence interval for the population mean of waiting
time.
To construct a confidence interval:
-Click on Stat
-Choose: T-statistics > One sample > with data
-Choose the variable Column
-Indicate Confidence Interval for μ, and then enter the level of confidence
-Click Compute
One sample T confidence interval:
μ : Mean of variable
99% confidence interval results: Variable Sample Mean Std. Err. DFL. LimitU. Limit
Waiting Time
4.71
0.35 19
3.71
5.71 3. Give an interpretation for the 90% confidence interval you calculated. (what conf. interval
mean (L and U))
We are 90% confident the mean waiting time of the drive-thru population during launch period is
between the interval (3.71 to 5.71). 4. Based on your confidence interval, is there evidence that the population mean waiting time is
less than 6 minutes? And why?
(Yes, because there is a strong confidence that the population
mean waiting time is between interval (3.71 to 5.71). ) …
5. You want to check if there evidence that the population mean waiting time is less than 6
minutes by using a hypothesis test with α = 0.01
To do t-test:
-Click on Stat
-Choose T statistics > One sample > with data
-Choose the variable Column
-Indicate Hypothesis Test, then enter the hypothesized Null mean, and choose the Alternative
hypothesis
-Click Compute.
One sample T hypothesis test:
μ : Mean of variable
H0 : μ = 6
HA : μ < 6
Hypothesis test results: Variable Sample Mean Std. Err. DF T-Stat P-value
Waiting Time
4.709
0.349 19 -3.70 0.0008
Based on the StatCrunch output, answer the following questions:
(a) State the hypotheses.
H0 : μ = 6
HA : μ < 6 (b) Find the test statistic.
T=-3.70
(c) Find the p-value.
P= 0.0008
(d) Provide an interpretation of the p-value within the context of the problem.
The p-value=0.0008 wich is the probability of the 20 randomly selected cars IF the null
hypothesis (the mean waiting time= 6) was true indicates that there’s only a very small chance
(e) Based on the p-value and the level of significance make a decision about H0.
Since p=0.0008 ≥ α=0.01, very low p-value shows strong evidence that the null hypothesis is
false. (reject H0 = 6, and support HA<6)
(f) Based on the decision write a conclusion in terms of the problem.

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Status NEW Posted 23 Aug 2017 06:08 AM My Price 10.00

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