QuickHelper

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About QuickHelper

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Teaching Since: May 2017
Last Sign in: 352 Weeks Ago, 5 Days Ago
Questions Answered: 20103
Tutorials Posted: 20155

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  • MBA, PHD
    Phoniex
    Jul-2007 - Jun-2012

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  • Corportae Manager
    ChevronTexaco Corporation
    Feb-2009 - Nov-2016

Category > Engineering Posted 30 Aug 2017 My Price 8.00

Find the product of the roots of the equation. 12x2 + x - 6,

Please take your time and double check ALL work for accuracy. Previous work received from tutors has had issues with incorrect answers.

Find the product of the roots of the equation.

12x2 + x - 6


a. 2/3

b. -3/4

c. -1/2

d. 1/2

========================================

Find the sum of the roots of the equation.

6x2 ­ - 5x + 1 = 0


a. 1/3

b. -­1/2

c. -5/6

d. 5/6

-------------------------------------------------------------

Solve the equation by factoring.

4x2 + 8x = 21


a. ¼ , ­21

b. 3/2, ­-7/2

c. 21/2, ­-1/2

d. 7, ­-¾

====================================

Solve the equation by factoring.

-2x2 + 12x ­- 16 = 0 


a. 4, 2

b. -4, ­-2

c. 8, ­-1

d. 8, 1

====================================

Solve the equation by factoring.

x2 + 5x ­ - 24 = 0


a. 2, -­12

b. ­-3, 8

c. -8, 3

d. 12, -­2

---------------------------------------------------------------

Factor the polynomial. 

5x2 ­ - 80


a. (x ­- 40)(5x + 2)

b. (x ­- 20)(5x + 4)

c. 5(x ­- 1)(x + 16)

d. 5(x -­ 4)(x + 4)

=================================

Factor the polynomial.

x2 ­ - 7x + 6


a. (x - ­ 6)(x ­ - 1)

b. (x ­ - 3)(x ­ - 2)

c. (x + 2)(x + 3)

d. (x + 1)(x + 6)

===================================

Factor the polynomial.

x2 + 8x ­- 9


a. (x ­- 3)(x + 3)

b. (x -­ 9)(x + 8)

c. (x + 1)(x -­ 9)

d. (x ­- 1)(x + 9)

=======================================

Which of the following equations would have the roots -½ and ⅗?

a. (2x - ­ 1)(5x + 3) = 0

b. (1x + 2)(3x ­- 5) = 0

c. (2x + 1)(5x - ­ 3) = 0

d. (1x - ­ 2)(3x + 5) = 0

=============================================

Which of the following equations would have the roots ­-3 and 2?


a. (x -­ 3)(x + 2) = 0

b. (2x + 6)(x - 2) = 0

c. (3x + 2)(x -­ 3) = 0

d. (2x + 3)(2x -­ 2) = 0

Answers

(10)
Status NEW Posted 30 Aug 2017 10:08 AM My Price 8.00

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