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  • MBA IT, Mater in Science and Technology
    Devry
    Jul-1996 - Jul-2000

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    Devry University
    Mar-2010 - Oct-2016

Category > Math Posted 21 Apr 2017 My Price 8.00

A travel company decides to advertise

Here is the original question:

A travel company decides to advertise in the Saturday travel sections of two major newspapers in town. The advertisements are directed at three groups of potential customers. Each advertisement in newspaper A is seen by 60,000 group I customers, 35,000 group II customers, and 22,000 group III customers. Each advertisement in newspaper B is seen by 9,700 group I, 19,500 group II, and 38,000 group III. Each advertisement in newspaper A costs $900.00, and each advertisement in newspaper B costs $700.00. The travel company would like their advertisement to be seen by at least 1,750,000 people from group I, at least 1,250,000 people from group II, and at least 900,000 people from group III. How many advertisements should the travel company place in each newspaper to achieve its advertising goals at a minimum cost? Let x be the number of advertisements in newspaper A and y be the number of advertisements in group B.

 

Determine the objective function:

            Minimize Z=900x+700y

 

 

 

 

Determine the system of inequalities required to consider minimizing the objective function: 

         60000x+9700y>= 1750000

         35000x+19500y>= 1250000

         22000x+38000y>=900000

 

MY QUESTION IS THIS:

How do I maximize p= x-3y subject to

  • 2x -3y <=6
  • -x +4y <=4
  • x >=0, y >=0

Answers

(11)
Status NEW Posted 21 Apr 2017 07:04 AM My Price 8.00

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file 1492761039-Solutions file 2.docx preview (51 words )
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