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Category > Chemistry Posted 15 May 2017 My Price 5.00

Molarity of Acid

Having trouble figuring out these problems, more information in the link. Show work please

 

Molarity of Acid = {Molarity of Base x Volume of Base} / Volume of Acid: Show work here:

                                = 0.5 M NaOH x (Average Volume NaOH) / 5 mL Vinegar

 

% CH3COOH = (Molarity of Acid / 60 g/mole) x 100% =

Show work here:

Post Lab Questions:

A)    If the manufacturer of the vinegar used in the experiment stated that the vinegar contained 5.0% acetic acid, what would the percent error between your result and the manufacturer’s statement be? Show your work.

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SuperTutor
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Status NEW Posted 15 May 2017 02:05 AM My Price 5.00

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