Help with percent yield. thank you
Exact mass of (E)-stilbene used: 2.038g
Exact mass of pyridium used : 4.083g
Pre-weighted boat: 0.988g
Mass of product 3.273g
                        -0.988g
                         2.285g
Help with theoretical and percent yield
Theoretical yield
# of moles reactant x (mole of product / mole reactant)
2.038g (E)-stilbene x (1 mole E-Stilbene/180.2488 g E-Stilbene) = 0.01131 moles E-Stilbene
0.01131 moles E-Stilbene x (340.0568g 1,2-Dibromo-1,2-diphenylethane /1 mole product) = 3.845g
Percent yield = (expected yield / theoretical yield) x 100 %
                      =(actual product/theoretical yield) x 100 %
what would be the limiting reactant
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Bromination of Stilbene lab would my product be pure and why based on the following data Melting point Crude: 236.4 - 240.2 ℃ Product 238.7-239.9 ℃ Lit melting point: 235-241℃
Answers
Status NEW
Posted 15 May 2017 02:05 AM
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