About Dr Nick

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Teaching Since:	May 2017
Last Sign in:	244 Weeks Ago, 6 Days Ago
Questions Answered:	19234
Tutorials Posted:	19224

Education

MBA (IT), PHD
Kaplan University
Apr-2009 - Mar-2014

Experience

Professor
University of Santo Tomas
Aug-2006 - Present

Category > Statistics Posted 10 Nov 2017 My Price 11.00

arrange them in increasing order and data appears as10,11,13,19,37

Range is $27$ and interquartile range is $17 \frac{1}{2}$

Let us first arrange them in increasing order and data appears as

$10, 11, 13, 19, 37$

As the range is difference between maximum and nimimum

Range is $37 - 10 = 27$

Median is the value of ${(\frac{n + 1}{2})}^{t h}$

term i.e. $\frac{5 + 1}{2} = 3^{r d}$ term i.e. $13$

First quartile $Q_{1}$

is ${(\frac{n + 1}{4})}^{t h} = {(1 \frac{1}{2})}^{t h}$ term and third quartile $Q_{3}$ is $3 {(\frac{n + 1}{4})}^{t h} = {(4 \frac{1}{2})}^{t h}$

term.

Hence, we can take $Q_{1}$

as $\frac{10 + 11}{2} = 10 \frac{1}{2}$ and $Q_{3}$ as $\frac{19 + 37}{2} = 28$

As interquartile range is $Q_{3} - Q_{1}$

, it is $28 - 10 \frac{1}{2} = 17 \frac{1}{2}$

Answers

Dr Nick

(3)

Status NEW Posted 10 Nov 2017 11:11 AM My Price 11.00

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