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Teaching Since: | May 2017 |
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MBA (IT), PHD
Kaplan University
Apr-2009 - Mar-2014
Professor
University of Santo Tomas
Aug-2006 - Present
Here's my initial answer. Requires refining from someone who understands probability better.
Each base can be ATCG. (4 possibilities)
EcoR1 recognizes a 6bp sequence, which is one out of 4^6 possibilities.
So for a 10kb linear fragment, there are (10k-5) such possibilities.
So number of cuts is 9995/(4^6)?
Or is there a better way to answer this?
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