Dr Nick

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About Dr Nick

Levels Tought:
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Teaching Since: May 2017
Last Sign in: 249 Weeks Ago, 1 Day Ago
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Education

  • MBA (IT), PHD
    Kaplan University
    Apr-2009 - Mar-2014

Experience

  • Professor
    University of Santo Tomas
    Aug-2006 - Present

Category > Statistics Posted 10 Nov 2017 My Price 15.00

the formula ##(n!)/((n_1!)(n_2!)...)##

In a word where no letters are repeated, such as FRANCE, the number of distinguishable ways of arranging the letters could be calculated by 5!, which gives 120. However, when letters are repeated, you must use the formula ##(n!)/((n_1!)(n_2!)...)##

There are 4 s's, 3 a's and a total of 9 letters.

##(9!)/((4!)(3!))##

= ##362880/(24 xx 6)##

= 2520

There are 2520 distinguishable ways of arranging the letters.

Practice exercises:

  1. Find the number of distinguishable ways of arranging the letters in the word EXERCISES.

  2. Find the number of distinguishable ways of arranging letters in the word AARDVARK.

Good luck!

Answers

Dr Nick
(3)
Status NEW Posted 10 Nov 2017 11:11 AM My Price 15.00

 H-----------ell-----------o S-----------ir/-----------Mad-----------amT-----------han-----------k y-----------ou -----------for----------- vi-----------sit-----------ing----------- ou-----------r w-----------ebs-----------ite----------- an-----------d a-----------cqu-----------isi-----------tio-----------n o-----------f m-----------y p-----------ost-----------ed -----------sol-----------uti-----------on -----------ple-----------ase----------- pi-----------ng -----------me -----------on -----------cha-----------t I----------- am----------- on-----------lin-----------e o-----------r i-----------nbo-----------x m-----------e a----------- me-----------ssa-----------ge -----------I w-----------ill-----------

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