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MBA, Ph.D in Management
Harvard university
Feb-1997 - Aug-2003
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Strayer University
Jan-2007 - Present
I am having a very hard time figuring out this problem. I need to exactly how you get the mass of the .90g and 1.10g . I know that the periodic table was for the total molar mass. I am so confused.
Â
mass of KAl(SO4)2 = 0.90 g
mass of H2O = 1.10 gÂ
Â
The ratio of moles of water to moles of anhydrous KAl(SO4)2Â is = 1 : 17
Explanation:
Given
Â
Therefore,
Moles of KAl(SO4)2 is = mass / total molar mass = ( 0.9 g ) / ( 39 + 23 + 64 + 128 ) = 0.00354 moles
and
Moles of H2O = ( 1.10 g ) / ( 2 + 16 ) = 0.0611 moles
Hence, the molar ratio of H2O / KAl(SO4)2 is = 0.0611 / 0.00354 = 17.2 = 1 : 17
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