C++

A local company, Molding Supreme, uses produces molds to cast various shapes.However, the molds become scratched after many uses and need to be replaced which costs a lot ofmoney. Therefore the company has been researching various formulations mold materials and heattreatments to produce a material that is not too expensive and that resists scratching. You are asked todevelop a program that will help the researchers analyze the data. The researchers use multipleformulations and apply various heat treatments to these formulations. The researchers need a programto determine the highest and second highest hardness for each formulation.Your program should ask the user to enter the formulation name. Next your program should ask theuser how many heat treatments were used for that formulation. The number of heat treatments must beat least 3. The user should then be prompted to enter a hardness value for each of the treatments of thatformulation and output the highest and second highest hardness for that formulation.Your code should use a single string object to store the name of the formulation, a while loop to checkthat the number of heat treatments is at least 3, a for loop to enter the hardness for each heat treatmentand determine the highest hardness and second highest hardness values, a while loop to ensure that thehardness is greater than 0 and less than or equal to 11 and a do-while loop to repeat for additionalformulations. Sample outputs are given below.

Make sure that your code follows the assignment guidelines posted on Canvas. Your code shouldnot use arrays or concepts beyond Chapter 5 of your textbook. Upload your source code as asubmission for Project 2.

 

 

CMPSC 201 – Spring 2017
Project 2
Due by 11:00 pm on Friday 3/3/17
Worth 45 pts
C++ goals: using loops
Problem: A local company, Molding Supreme, uses produces molds to cast various shapes.
However, the molds become scratched after many uses and need to be replaced which costs a lot of
money. Therefore the company has been researching various formulations mold materials and heat
treatments to produce a material that is not too expensive and that resists scratching. You are asked to
develop a program that will help the researchers analyze the data. The researchers use multiple
formulations and apply various heat treatments to these formulations. The researchers need a program
to determine the highest and second highest hardness for each formulation.
Your program should ask the user to enter the formulation name. Next your program should ask the
user how many heat treatments were used for that formulation. The number of heat treatments must be
at least 3. The user should then be prompted to enter a hardness value for each of the treatments of that
formulation and output the highest and second highest hardness for that formulation.
Your code should use a single string object to store the name of the formulation, a while loop to check
that the number of heat treatments is at least 3, a for loop to enter the hardness for each heat treatment
and determine the highest hardness and second highest hardness values, a while loop to ensure that the
hardness is greater than 0 and less than or equal to 11 and a do-while loop to repeat for additional
formulations. Sample outputs are given below.
Make sure that your code follows the assignment guidelines posted on Canvas. Your code should
not use arrays or concepts beyond Chapter 5 of your textbook. Upload your source code as a
submission for Project 2.
Output 1:
What is the name of the formulation? Tungsten Carbide 451
How many heat treatments were used for formulation Tungsten Carbide 451? 5
Enter
Enter
Enter
Enter
Enter the
the
the
the
the hardness
hardness
hardness
hardness
hardness for
for
for
for
for treatment
treatment
treatment
treatment
treatment 1
2
3
4
5 of
of
of
of
of formulation
formulation
formulation
formulation
formulation Tungsten
Tungsten
Tungsten
Tungsten
Tungsten Carbide
Carbide
Carbide
Carbide
Carbide The highest hardness for Tungsten Carbide 451 was 10.02 mohs
and the second highest hardness was 9.93 mohs.
Are there more formulations? (y/n) n 451.
451.
451.
451.
451. 9.89
8.34
9.93
8.99
10.02 Output 2:
What is the name of the formulation? Wolfram 162
How many heat treatments were used for formulation Wolfram 162? 2
Enter the hardness for treatment 1 of formulation Wolfram 162. 10.05
Enter the hardness for treatment 2 of formulation Wolfram 162. 9.89
Enter the hardness for treatment 3 of formulation Wolfram 162. 0
The hardness must be greater than zero and less than or equal to 11!
Enter the hardness for treatment 3 of formulation Wolfram 162. 10.07
Enter the hardness for treatment 4 of formulation Wolfram 162. 12.15
The hardness must be greater than zero and less than or equal to 11!
Enter the hardness for treatment 4 of formulation Wolfram 162. 11.15
The hardness must be greater than zero and less than or equal to 11!
Enter the hardness for treatment 4 of formulation Wolfram 162. 10.15
Enter the hardness for treatment 5 of formulation Wolfram 162. 10.23
Enter the hardness for treatment 6 of formulation Wolfram 162. 10.01
Enter the hardness for treatment 7 of formulation Wolfram 162. 10.30 The highest hardness for Wolfram 162 was 10.3 mohs
and the second highest hardness was 10.23 mohs.
Are there more formulations? (y/n) y What is the name of the formulation? Stabilized Saphire
How many heat treatments were used for formulation Stabilized Saphire? 2
There must be at least 3 heat treatments for each formulation!
How many heat treatments were used for formulation Stabilized Saphire? 5
Enter the hardness for treatment 1 of formulation Stabilized Saphire. 8.98
Enter the hardness for treatment 2 of formulation Stabilized Saphire. 9.25
Enter the hardness for treatment 3 of formulation Stabilized Saphire. 8.45
Enter the hardness for treatment 4 of formulation Stabilized Saphire. 8.23
Enter the hardness for treatment 5 of formulation Stabilized Saphire. 8.48 The highest hardness for Stabilized Saphire was 9.25 mohs
and the second highest hardness was 8.98 mohs.
Are there more formulations? (y/n) n For 5 points of extra credit design your program to output treatment number corresponding to
the highest hardness and the second highest hardness as well as the hardness values. You may
not ask the TAs, graders or Dr. Quick for help on the extra credit. Example output message for
this modification is given below Treatment 2 produced the highest hardness for Stabilized Saphire of 9.25 mohs
and treatment 1 produced the second highest hardness of 8.98 mohs.

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