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    New york Institute of Technology
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    NYIT
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    NYIT
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Category > Accounting Posted 25 Jun 2017 My Price 4.00

Experimental data was collected for the following reaction

Experimental data was collected for the following reaction: 2A + B → C

experiment
[A] (M)
[B] (M)
initial rate M/s
1
0.550
0.300
7.11 × 10–4
2
0.550
0.150
3.56 × 10–4
3
0.278
0.150
3.56 × 10–4

Determine the rate law and calculate the rate constant for the chemical reaction.
 1. rate = 7.90 × 10–3[A][B]2

2. rate = 2.37 × 10–3[B]2

3. rate = 7.90 × 10–3 [B]2

4. rate = 2.37 × 10–3 [B]

Answers

Math Expert
(3)
Status NEW Posted 25 Jun 2017 05:06 PM My Price 4.00

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file 1498411170-Small Answer.docx preview (67 words )
4-----------. r-----------ate----------- = -----------2.3-----------7 *-----------10------------3[B-----------] -----------Exp-----------lan-----------ati-----------on:----------- l-----------ets----------- sa-----------y k----------- = -----------rat-----------e c-----------ons-----------tan-----------t -----------7.1-----------1 *-----------10------------4 -----------= k-----------[0.-----------550-----------]m[-----------0.3-----------]nÂ----------- ..-----------...-----------...-----------...-----------..e-----------qn -----------1 -----------3.5-----------6 *----------- 10------------4Â----------- = -----------k[0-----------.55-----------0]m-----------[0.-----------15]-----------n -----------...-----------...-----------...-----------...-----------.eq-----------n 2----------- d-----------ivi-----------din-----------g e-----------qn -----------1 w-----------ith----------- eq-----------n 2----------- we----------- ge-----------t, ----------- 2 -----------= 2-----------n -----------n =----------- 1 ----------- 3.-----------56 -----------* 1-----------0-4----------- =----------- k[-----------0.5-----------50]-----------m[0-----------.15-----------0]n----------- .-----------...-----------...-----------..e-----------qn -----------3 -----------3.5-----------6 *-----------10------------4 -----------= k-----------[0.-----------278-----------]m[-----------0.1-----------5]n----------- .-----------...-----------...-----------...-----------...-----------eqn----------- 4 ----------- di-----------vid-----------ing----------- eq-----------n 3----------- wi-----------th -----------eqn----------- 4 -----------we -----------get-----------, -----------1 =----------- 2m----------- m----------- = -----------0 -----------3.5-----------6 *----------- 10------------4Â----------- = -----------k[0-----------.27-----------8]0-----------[0.-----------150-----------]1 ----------- 3.-----------56 -----------* 1-----------0-4----------- =----------- k[-----------0.1-----------5] -----------
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