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MBA IT, Mater in Science and Technology
Devry
Jul-1996 - Jul-2000
Professor
Devry University
Mar-2010 - Oct-2016
For Programming Assignment 3 you will be creating a program to manage cars in a dealership.  This will again be a menu driven system. The following is your menu:
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Your program will be class based with the following UML representing the classes:
Dealer
- DealerName: string
- DealerAddress: string
+ setName( input:string): void
+ setAddress(input:string ): void
+ getName( ): string
+ getAddress( ): string
+ Dealer ( );
+ Dealer ( iName:string) ;
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Vehicle
- VIN:string
- make:string
- model:string
- year:int
- price:double
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+ DealerPtr: Dealer *Â Â //Note this should be in the public area
+ Vehicle(iVIN:string, iMake:string, iModel:string, iYear:int, iPrice:double)
+ Vehicle( )
+ getVIN( ):string
+ getMake( ):string
+ getModel( ):string
+ getYear( ):int
+ getPrice( ):double
+ setVIN(input:string):void
+ setMake(input:string):void
+ setModel(input:string):void
+ setYear(input:int):void
+ setPrice(input:double):void
+ friend operator << (out: ostream &, Vehicle: car 1):ostream &
 //Note: Don't forget to create a new Dealer if either the Vehicle constructor or default constructor is called.
You will have four files for your program (Use these file names!): main.cpp, functions.h, vehicle.h, vehicle.cpp. Place into a file folder named LastnamePA3, the zip the content and hand in a zip file!
You will be storing your vehicle objects in a vector. In the main function, you will create a vector of vehicles with an initial size of zero (0). When the menu options display, delete, edit, sort, or search are called, you will have to check your vector and ensure that it has a vehicle in it before the function continues (error checking).
You will not have any global variables.
Each menu item will have a corresponding function, and the definition of the function will be found in the file functions.h. Each function will only have one parameter, the vector. All I/O will be done in the functions and not in main (expect asking for what menu option the user wants).
The following are the details for each of your menu options:
Vehicle:Â #
VIN:Â VVVV
Make:Â MMMM
Model:Â MMMM
Year:Â YYYY
Price:Â $D.CC
Dealer Name:Â DDDDDD
Dealer Address:Â AAAAAAAAAA
The bold face letters represent the values for the individual vehicle, and it doesn’t have to be bolded. Notice the tab stop between the label and the value. Also notice that there is a dollar sign and decimal for the price. Lastly, for Vehicle: #, the pound sign represents the vehicle position number in the vector (starting at 1 not 0), which will be 1, 2, 3 … and so on.
2. You will ask the user for all of the information to add the vehicle and then you will add it to the vector.
3. You will display the vehicles and then ask the user which vehicle to edit; they will give you the index number (starting at 1). Check to ensure they gave you a valid entry, then prompt for which item they want to edit (year, make, model, price, or VIN). Once they make their selection prompt for the new information, then return to the main menu.
4. You will display the vehicles and then ask the user which vehicle to delete: they will give you the index number (starting at 1). You will then check to ensure they gave you a valid entry and then remove that vehicle from the vector.
5. You will sort the vector by VIN number (when sort is done, the vector in main will be sorted by VIN number).
6. You will ask the user for a model, then search the vector for that vehicle. You will return the first matching entry’s index number or an appropriate message if not found.
7. You will read the inventory from a file called inventory.txt, which is NOT provided for you (you will need to make your own to start with). The data is stored in the same order as listed above and is newline delimited (like the example below).
34ABC321B
BMW
328xi
2016
41315.00
Schomp BMW
Littleton, CO
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8. You will write the entire inventory out to a file called inventory.out (using the << operator) and then exit the program.
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Rubric
Programming Assignment Rubric (1)
| Correct Output (Logic & Completeness) view longer description | Â | 25.0Â pts | |
| No Compiler Errors (Syntax) | Â | 4.0Â pts | |
| Comments Used | Â | 3.0Â pts | |
| Variable Naming & Formatting Conventions Followed | Â | 3.0Â pts | |
| Total Points:Â 35.0 | |||
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