I need help on an assembly language assignment (MIPS)

The first attached file is my assignment

The second attached file is what I have so far (may not be completely correct)

 

Exercise 1:a.) I-typeOpcode: 000100 (6-bit operaTon code binary representaTon of the beq instrucTon; if ($rs == $rt) pc += i<< 2)rs: $t2$1001010 (5-bit binary representaTon of the Frst source register address)rt: $zero$000000 (5-bit binary representaTon of the second source register address)imm: strlen_end_loop0000000000000110 (since the branch target is 6 instrucTons past the beq, weadded a binary 6 to 0000000000000000 to show the o±set of 6).32-bit binary representaTon: 000000 01010 00000 0000000000000110 (added leading zeros to Fll upthe rest of the spots)convert to 8-bit hexadecimal: 0x0140_0006b.) If the code branched backwards to strlen_begin_loop instead, there would be an o±set of -4 insteadof 6.Opcode: 000100 (6-bit operaTon code binary representaTon of the beq instrucTon; if ($s == $t) pc += i<< 2)rs: $t2$1001010 (5-bit binary representaTon of the Frst source register address)rt: $zero$000000 (5-bit binary representaTon of the second source register address)imm: strlen_begin_loop1111111111111100 (since the branch target is 4 instrucTons behind the beq,we subtracted a binary 4 from 0000000000000000 to show the o±set of -4).32-bit binary representaTon: 000000 01010 00000 1111111111111100 (added leading zeros to Fll upthe rest of the spots)convert to 8-bit hexadecimal: 0x0140_²²²Cc.) J-typeOpcode: 000010 (6-bit operaTon code binary representaTon of the j instrucTon; pc += i << 2)³arget address of strlen_begin_loop: 00000000000000000000000000 – 8 (since the branch target is 8steps behind the j instrucTon)32-bit binary representaTon: 000010 00000000000000000000000000convert to 8-bit hexadecimal: 0x0800_0000

 

 

• 1494233126-CSE230_HW5.docx

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Status NEW Posted 08 May 2017 08:05 AM My Price 9.00

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