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Category > Applied Sciences Posted 08 May 2017 My Price 5.00

Using recursion, compute the area of a polygon

Using recursion, compute the area of a polygon. Cut off a triangle and use the fact that a triangle with corners (x1, y1), (x2, y2), (x3, y3) has area

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Status NEW Posted 08 May 2017 11:05 AM My Price 5.00

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file 1494242303-Answer.docx preview (116 words )
U-----------sin-----------g r-----------ecu-----------rsi-----------on,----------- co-----------mpu-----------te -----------the----------- ar-----------ea -----------of -----------a p-----------oly-----------gon-----------. C-----------ut -----------off----------- a -----------tri-----------ang-----------le -----------and----------- us-----------e t-----------he -----------fac-----------t t-----------hat----------- a -----------tri-----------ang-----------le -----------wit-----------h c-----------orn-----------ers----------- (x-----------1, -----------y1)-----------, (-----------x2,----------- y2-----------), -----------(x3-----------, y-----------3) -----------has----------- ar-----------ea ----------- -----------Ans-----------wer----------- p-----------ubl-----------ic -----------cla-----------ss -----------Pol-----------ygo-----------nAr-----------ea -----------{ /-----------/me-----------tho-----------d t-----------o c-----------alc-----------ula-----------te -----------are-----------a p-----------oly-----------gon----------- re-----------cur-----------siv-----------ely----------- pu-----------bli-----------c s-----------tat-----------ic -----------dou-----------ble----------- Re-----------cur-----------siv-----------eAr-----------eaP-----------oly-----------gon-----------(do-----------ubl-----------e[]----------- x_-----------val-----------ues-----------, d-----------oub-----------le[-----------] y-----------_va-----------lue-----------s, -----------int----------- in-----------dex-----------, d-----------oub-----------le -----------are-----------a) -----------{ i-----------f (-----------ind-----------ex -----------== -----------4) -----------{ r-----------etu-----------rn -----------are-----------a; -----------} e-----------lse----------- { -----------are-----------a =----------- ar-----------ea -----------+ (-----------x_v-----------alu-----------es[-----------0] -----------* y-----------_va-----------lue-----------s[i-----------nde-----------x +----------- 1]-----------
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