AccountingQueen

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  • MBA.Graduate Psychology,PHD in HRM
    Strayer,Phoniex,
    Feb-1999 - Mar-2006

  • MBA.Graduate Psychology,PHD in HRM
    Strayer,Phoniex,University of California
    Feb-1999 - Mar-2006

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Category > Math Posted 19 Aug 2017 My Price 5.00

The probability

1.6 pointsFour events A, B, C, and D are such that A and B are mutually ex- clusive (disjoint) and D is contained in (A ∪ B ∪ C)t. Moreover, P (B ∩ C) is twice as likely as P (A ∩ C), while P (A ∩ Ct) = P (B ∩ Ct) = 0.2, P (D) = P [(A ∪ B ∪ C ∪ D)t] = P (C ∩ At ∩ Bt) = 0.1. Find:

(a)1 pointsThe probability that none of the events occur.

 

 

 

 

(b)2 pointsThe probability that exactly two of the events occur.

 

 

 

 

(c)1 pointsThe probability that at most two of the events occur.

 

 

 

 

(d)2 pointsThe probability that exactly one of the events occur.

Answers

AccountingQueen
(3)
Status NEW Posted 19 Aug 2017 06:08 AM My Price 5.00

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