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Category > Statistics Posted 09 May 2017 My Price 4.00

Suppose we pick a card at random from an ordinary 52-card

Suppose we pick a card at random from an ordinary 52-card deck and also flip 10 fair coins. What is the probability that the number of heads equals the value of the card (where we count jacks, queens, and kings as 10, and count aces as 1)?

 

 

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Status NEW Posted 09 May 2017 10:05 AM My Price 4.00

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file 1494325645-Answer.docx preview (122 words )
S-----------upp-----------ose----------- we----------- pi-----------ck -----------a c-----------ard----------- at----------- ra-----------ndo-----------m f-----------rom----------- an----------- or-----------din-----------ary----------- 52------------ca-----------rd -----------dec-----------k a-----------nd -----------als-----------o f-----------lip----------- 10----------- fa-----------ir -----------coi-----------ns.----------- Wh-----------at -----------is -----------the----------- pr-----------oba-----------bil-----------ity----------- th-----------at -----------the----------- nu-----------mbe-----------r o-----------f h-----------ead-----------s e-----------qua-----------ls -----------the----------- va-----------lue----------- of----------- th-----------e c-----------ard----------- (w-----------her-----------e w-----------e c-----------oun-----------t j-----------ack-----------s, -----------que-----------ens-----------, a-----------nd -----------kin-----------gs -----------as -----------10,----------- an-----------d c-----------oun-----------t a-----------ces----------- as----------- 1)-----------? ----------- A-----------nsw-----------er ----------- P(-----------X=1-----------) =----------- (1-----------/13-----------) *----------- 10-----------C1 -----------* (-----------0.5-----------)^1----------- * -----------(0.-----------5)^-----------9 =----------- (-----------1/1-----------3) -----------* 1-----------0C1----------- * -----------(0.-----------5)^-----------10 -----------= 0-----------.00-----------075-----------1 P-----------(X=-----------2) -----------= (-----------1/1-----------3) -----------* 1-----------0C2----------- *----------- (0-----------.5)-----------^2Â----------- * -----------(0.-----------5)^-----------8 -----------= -----------(1/-----------13)----------- * -----------10C-----------2 -----------* (-----------0.5-----------)^1-----------0 =----------- 0.-----------003-----------38 -----------P(X-----------=3)----------- = -----------(1/-----------13)-----------
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