Maurice Tutor

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Teaching Since: May 2017
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    Argosy University/ Phoniex University/
    Nov-2005 - Oct-2011

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    Phoniex University
    Oct-2001 - Nov-2016

Category > Computer Science Posted 27 Aug 2017 My Price 8.00

nonzero scalar

Consider a system with state matrices

(a) Use feedback of the form is a nonzero scalar, to move the poles to – 3 ± 3j. (b) Choose  so that if r is a constant, the system has zero steady-state error; that is y(∞) = r.

(c) Show that if F changes to F + δF, where δF is an arbitrary 2 × 2 matrix, then your choice of in part (b) will no longer make y(∞) = r. Therefore, the system is not robust under changes to the system parameters in F.

(d) The system steady-state error performance can be made robust by augmenting the system with an integrator and using unity feedback—that is, by setting I = r – y, where xI is the state of the integrator. To see this, first use state feedback of the form u = –Kx – K1x1 so that the poles of the augmented system are at

(e) Show that the resulting system will yield y(∞) = r no matter how the matrices F and G are changed, as long as the closed-loop system remains stable.

(f) For part (d), use MATLAB (SIMULINK) software to plot the time response of the system to a constant input. Draw Bode plots of the controller, as well as the sensitivity function (S) and the complementary sensitivity function (T).

Answers

Maurice Tutor
(5)
Status NEW Posted 27 Aug 2017 02:08 PM My Price 8.00

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