Maurice Tutor

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    Argosy University/ Phoniex University/
    Nov-2005 - Oct-2011

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    Phoniex University
    Oct-2001 - Nov-2016

Category > Computer Science Posted 14 Sep 2017 My Price 5.00

linear equation

*3.25      (Geometry: intersecting point) Two points on line 1 are given as (x1, y1) and (x2,

y2) and on line 2 as (x3, y3) and (x4, y4), as shown in Figure 3.8a–b.

The intersecting point of the two lines can be found by solving the following linear equation:

(y1  - y2)x  - (x1  - x2)y = (y1  - y2)x1  - (x1  - x2)y1

(y3  - y4)x  - (x3  - x4)y = (y3  - y4)x3  - (x3  - x4)y3

This linear equation can be solved using Cramer’s rule (see Programming Exer- cise 3.3). If the equation has no solutions, the two lines are parallel (Figure 3.8c).

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Maurice Tutor
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Status NEW Posted 14 Sep 2017 12:09 PM My Price 5.00

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