Maurice Tutor

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Teaching Since: May 2017
Last Sign in: 398 Weeks Ago, 6 Days Ago
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  • MCS,PHD
    Argosy University/ Phoniex University/
    Nov-2005 - Oct-2011

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  • Professor
    Phoniex University
    Oct-2001 - Nov-2016

Category > Computer Science Posted 14 Sep 2017 My Price 4.00

efficient approach

*7.6 (Revise Listing 5.15, PrimeNumber.java) Listing 5.15 determines whether a num- ber n is prime by checking whether 2, 3, 4, 5, 6, ..., n/2 is a divisor. If a divisor is found, n is not prime. A more efficient approach is to check whether any of the prime numbers less than or equal to 2n can divide n evenly. If not, n is prime. Rewrite Listing 5.15 to display the first 50 prime numbers using this approach. You need to use an array to store the prime numbers and later use them to check whether they are possible divisors for n.

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Maurice Tutor
(5)
Status NEW Posted 14 Sep 2017 12:09 PM My Price 4.00

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