Maurice Tutor

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  • MCS,PHD
    Argosy University/ Phoniex University/
    Nov-2005 - Oct-2011

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    Phoniex University
    Oct-2001 - Nov-2016

Category > Computer Science Posted 14 Sep 2017 My Price 4.00

triple for stack generability

1.3.46 Forbidden triple for stack generability. Prove that a permutation can be generated by a stack (as in the previous question) if and only if it has no forbidden triple (a, b, c) such that a < b < c with c fi rst, a second, and b third (possibly with other intervening integers between c and a and between a and b). Partial solution: Suppose that there is a forbidden triple (a, b, c). Item c is popped before a and b, but a and b are pushed before c. Thus, when c is pushed, both a and b are on the stack. Therefore, a cannot be popped before b.

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Maurice Tutor
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Status NEW Posted 14 Sep 2017 06:09 PM My Price 4.00

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