Write code to complete DoublePennies()'s base case. Sample output for below program:

Number of pennies after 10 days: 1024

#include <stdio.h>

// Returns number of pennies if pennies are doubled numDays times
long long DoublePennies(long long numPennies, int numDays){
long long totalPennies = 0;

/* Your solution goes here */

else {
totalPennies = DoublePennies((numPennies * 2), numDays - 1);
}

return totalPennies;
}

// Program computes pennies if you have 1 penny today,
// 2 pennies after one day, 4 after two days, and so on
int main(void) {
long long startingPennies = 0;
int userDays = 0;

startingPennies = 1;
userDays = 10;
printf("Number of pennies after %d days: %lld\n", userDays, DoublePennies(startingPennies, userDays));

return 0;
}