Maurice Tutor

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    Argosy University/ Phoniex University/
    Nov-2005 - Oct-2011

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    Phoniex University
    Oct-2001 - Nov-2016

Category > Computer Science Posted 15 Sep 2017 My Price 7.00

fraction part

Hi, i have problems with these three. The problem i have, is that when i need to specify the fraction part. i obtain 17bit. based on the IEEE754-2008 i take 1 bit for the sign. 5 bits for the exponent. 10 bits to mantissa. so i take the other 7 bits of my binary number after the floating point: 1 to guard bit, 1 to the round, and the other 5 to my sticky bit. after that the values i obtain are: the guard bit is 1, the round bit is 0 and the lsb of the sticky bit is 0. but what happend if these case. what rules i need to follow. Thanks.

The Bias based on IEEE 754-2008 is 15

|sing 1bit|exponent 5 bits|mantissa 10 bits|

Calculate (3.984375A????110?1 + 3.4375A????110?1)+ 1.771A????1103 by hand, assuming each of the values are
stored in the 16-bit half precision. Assume 1 guard, 1 round bit, and 1 sticky bit, and round to the nearest even. show all the steps, and write your answer in both the 16-bit floating point format and in decimal.

Calculate 3.984375A????110?1 + (3.4375A????110?1 + 1.771A????1103) by hand, assuming each of the values are
stored in the 16-bit half precision. Assume 1 guard, 1 round bit, and 1 sticky bit, and round to the nearest even. Show all the steps, and write your answer in both the 16-bit floating point format and in decimal.

Based on your answers to 3.32 and 3.33, does (3.984375 A????1 10?1 + 3.4375 A????1 10?1) + 1.771 A????1 103 =3.984375 A????1 10?1 + (3.4375 A????1 10?1 + 1.771 A????1 103)

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Maurice Tutor
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Status NEW Posted 15 Sep 2017 01:09 PM My Price 7.00

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