Maurice Tutor

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About Maurice Tutor

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Algebra,Applied Sciences,Biology,Calculus,Chemistry,Economics,English,Essay writing,Geography,Geology,Health & Medical,Physics,Science Hide all
Teaching Since: May 2017
Last Sign in: 406 Weeks Ago, 5 Days Ago
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Education

  • MCS,PHD
    Argosy University/ Phoniex University/
    Nov-2005 - Oct-2011

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  • Professor
    Phoniex University
    Oct-2001 - Nov-2016

Category > Computer Science Posted 21 Sep 2017 My Price 5.00

half precision

1. Based on your answers to 3.32 and 3.33, does (3.984375 × 10-1 + 3.4375 × 10-1) + 1.771 × 103 = 3.984375 × 10-1 + (3.4375 × 10-1 + 1.771 × 103)?

2. Calculate (3.41796875 10-3×6.34765625 × 10-3 ) × 1.05625 × 102 by hand, assuming each of the values are stored in the 16-bit half precision format described in Exercise 3.27 (and also described in the text). Assume 1 guard, 1 round bit, and 1 sticky bit, and round to the nearest even. Show all the steps, and write your answer in both the 16-bit floating point format and in decimal.

Exercise 3.27

IEEE 754-2008 contains a half precision that is only 16 bits wide. The left most bit is still the sign bit, the exponent is 5 bits wide and has a bias of 15, and the mantissa is 10 bits long. A hidden 1 is assumed. Write down the bit pattern to represent -1.5625 × 10-1 assuming a version of this format, which uses an excess-16 format to store the exponent. Comment on how the range and accuracy of this 16-bit floating point format compares to the single precision IEEE 754 standard.

 

Answers

Maurice Tutor
(5)
Status NEW Posted 21 Sep 2017 10:09 PM My Price 5.00

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