Maurice Tutor

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    Argosy University/ Phoniex University/
    Nov-2005 - Oct-2011

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    Phoniex University
    Oct-2001 - Nov-2016

Category > Management Posted 12 Nov 2017 My Price 5.00

voltage source

Kirchoff’s equations for the circuit shown are

Differentiating Eq. (b) and substituting the charge–current relationship dq2/dt = i2, we get

We could substitute di1/dt from Eq. (c) in to Eq. (d), so that the latter would assume the usual form di2/dt = f(t,i1,i2),but it is more convenient to leave the equations as they are. Assuming that the voltage source is turned on at time t = 0, plot the loop currents i1 and i2 from t = 0 to 0.05 s. Use E(t) = 240 sin(120πt) V, R = 1.0 Ω, L = 0.2 × 10−3 H and C = 3.5 × 10−3 F.

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Maurice Tutor
(5)
Status NEW Posted 12 Nov 2017 11:11 AM My Price 5.00

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