Maurice Tutor

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About Maurice Tutor

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Expertise:
Algebra,Applied Sciences See all
Algebra,Applied Sciences,Biology,Calculus,Chemistry,Economics,English,Essay writing,Geography,Geology,Health & Medical,Physics,Science Hide all
Teaching Since: May 2017
Last Sign in: 408 Weeks Ago, 5 Days Ago
Questions Answered: 66690
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Education

  • MCS,PHD
    Argosy University/ Phoniex University/
    Nov-2005 - Oct-2011

Experience

  • Professor
    Phoniex University
    Oct-2001 - Nov-2016

Category > Management Posted 06 Jan 2018 My Price 4.00

watts of electrical power

Optional exercise: New York City requires about 1010 watts of electrical power, at 115 volts12 (this is plausible:10 million people averaging 1 kilowatt each). A heavy power cable might be an inch in diameter. Let’s calculate what will happen if we try to supply the power through a cable 1 foot in diameter made of pure copper. Its resistance is 0.05 μΩ (5×10−8 ohms) per foot. Calculate (a) the power lost per foot from “I2R losses,” (b) the length of cable over which you will lose all 1010 watts, and (c) how hot the cable will get, if you know the physics involved (σ = 6×10−12W/K4 cm2). If you have done your computations correctly, the result should seem preposterous. What is the solution to this puzzle?

Answers

(5)
Status NEW Posted 06 Jan 2018 05:01 PM My Price 4.00

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