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MCS,PHD
Argosy University/ Phoniex University/
Nov-2005 - Oct-2011
Professor
Phoniex University
Oct-2001 - Nov-2016
Another way to fill in the "missing link" in Fig. 5.48 is to look for a magnetostatic analog to Eq. 2.21. The obvious candidate would be
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(a) Test this formula for the simplest possible case-uniform B (use the origin as your reference point). Is the result consistent with Prob. 5.25? You could cure this problem by throwing in a factor of Â
, but the flaw in this equation runs deeper.
(b) Show that
(B x dl) is not independent of path, by calculating f (B x dl) around the rectangular loop shown in Fig. 5.63.

As far as I know,28 the best one can do along these lines is the pair of equations

(c) Use (ii) to find the vector potential for uniform B.
(d) Use (ii) to find the vector potential of an infinite straight wire carrying a steady current I. Does (ii) automatically satisfy ∇ · A = 0?


Prob. 5.25
If B is uniform, show that A(r) = -
(r x B) works. That is, check that ∇ · A = 0 and ∇ x A = B. Is this result unique, or are there other functions with the same divergence and curl?
Â
Â
Â
Â
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