Maurice Tutor

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About Maurice Tutor

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Expertise:
Algebra,Applied Sciences See all
Algebra,Applied Sciences,Biology,Calculus,Chemistry,Economics,English,Essay writing,Geography,Geology,Health & Medical,Physics,Science Hide all
Teaching Since: May 2017
Last Sign in: 408 Weeks Ago
Questions Answered: 66690
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Education

  • MCS,PHD
    Argosy University/ Phoniex University/
    Nov-2005 - Oct-2011

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  • Professor
    Phoniex University
    Oct-2001 - Nov-2016

Category > Management Posted 04 Feb 2018 My Price 8.00

inequality for absolute value

For another interesting example, let X = R2 and define d1 by

 

where the inequality comes from the triangle inequality for absolute value [Theorem 2.9(d)]. Geometrically, the neighborhoods in this metric are diamond shaped. [See Figure 2(b).] If (X,d) is a metric space, then we can use Definition 6.3 for neighborhoods to characterize interior points, boundary points, open sets, and closed sets, just as we did in Section 4 for R. The theorems from Section 4 that relate to these concepts also carry over to this more general setting with little or no change in their proofs. One result that should not be unexpected but that requires a new proof is the following theorem.

Answers

Maurice Tutor
(5)
Status NEW Posted 04 Feb 2018 07:02 PM My Price 8.00

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