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| Teaching Since: | May 2017 |
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| Questions Answered: | 66690 |
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MCS,PHD
Argosy University/ Phoniex University/
Nov-2005 - Oct-2011
Professor
Phoniex University
Oct-2001 - Nov-2016
Let n be a negative integer and let f(x) = xn for x ≠0. Note that – n is positive and if g(x) = x – n , then f(x) = (1/g)(x). Use Example 1.8 and the quotient rule of Theorem 1.7 to show that f ′(x) = nxn – 1. We know that the composition of two continuous functions is continuous. A similar result holds for the composition of differentiable functions, and it is known as the chain rule.
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Example 1.8
To illustrate the use of Theorem 1.7, let us show that for any n ∈ N, if f (x) = xn for all x ∈ R, then f ′(x) = nxn – 1 for all x ∈ R. Our proof is by induction. When n = 1 we have f (x) = x, so that

Theorem 1.7
Suppose that f : I → R and g : I → R are differentiable at c ∈ I. Then
(a) If k ∈ R, then the function kf is differentiable at c and

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