Maurice Tutor

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About Maurice Tutor

Levels Tought:
Elementary,Middle School,High School,College,University,PHD

Expertise:
Algebra,Applied Sciences See all
Algebra,Applied Sciences,Biology,Calculus,Chemistry,Economics,English,Essay writing,Geography,Geology,Health & Medical,Physics,Science Hide all
Teaching Since: May 2017
Last Sign in: 408 Weeks Ago
Questions Answered: 66690
Tutorials Posted: 66688

Education

  • MCS,PHD
    Argosy University/ Phoniex University/
    Nov-2005 - Oct-2011

Experience

  • Professor
    Phoniex University
    Oct-2001 - Nov-2016

Category > Management Posted 04 Feb 2018 My Price 8.00

list of distinct members


Let S be a countable set and let T ⊆ S. Then T is countable. If T is finite, then we are done. Thus we may assume that T is infinite. This implies (Exercise 6) that S is infinite, so S is denumerable (since it is countable). Therefore, there exists a bijection f: N → S and we can write S as a list of distinct members

 

Since A is a nonempty subset of N, the Well-Ordering Property of ` implies A has a least member, say a1. Similarly, the set A\{a1} has a least member, say a2. In general, having chosen a1,…, ak, let ak +1 be the least member in A\{a1,…, ak}. Essentially, if we select from our listing of S those terms that are in T and keep them in the same order, then an is the subscript of the nth term in this new list. Now define a function g: N → N by g(n) = an. Since T is infinite, g is defined for every n ∈ N. Since an +1 ∉ {a1,…, an}, g must be injective. Thus the composition f ° g is also injective. Since each element of T is somewhere in the listing of S, g(N) includes all the subscripts of terms in T. Thus f ° g is a bijection from N onto T and T is denumerable. Using Theorem 4.9, we can derive two very useful criteria for determining when a set is countable.

Answers

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Status NEW Posted 04 Feb 2018 07:02 PM My Price 8.00

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