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| Teaching Since: | May 2017 |
| Last Sign in: | 408 Weeks Ago |
| Questions Answered: | 66690 |
| Tutorials Posted: | 66688 |
MCS,PHD
Argosy University/ Phoniex University/
Nov-2005 - Oct-2011
Professor
Phoniex University
Oct-2001 - Nov-2016
Let S be a countable set and let T ⊆ S. Then T is countable. If T is finite, then we are done. Thus we may assume that T is infinite. This implies (Exercise 6) that S is infinite, so S is denumerable (since it is countable). Therefore, there exists a bijection f: N → S and we can write S as a list of distinct members
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Since A is a nonempty subset of N, the Well-Ordering Property of ` implies A has a least member, say a1. Similarly, the set A\{a1} has a least member, say a2. In general, having chosen a1,…, ak, let ak +1 be the least member in A\{a1,…, ak}. Essentially, if we select from our listing of S those terms that are in T and keep them in the same order, then an is the subscript of the nth term in this new list. Now define a function g: N → N by g(n) = an. Since T is infinite, g is defined for every n ∈ N. Since an +1 ∉ {a1,…, an}, g must be injective. Thus the composition f ° g is also injective. Since each element of T is somewhere in the listing of S, g(N) includes all the subscripts of terms in T. Thus f ° g is a bijection from N onto T and T is denumerable. Using Theorem 4.9, we can derive two very useful criteria for determining when a set is countable.
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