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    Oct-2001 - Nov-2016

Category > Management Posted 17 Feb 2018 My Price 9.00

Innovation Management

Characteristics of lead users. Refer to the Creativity and Innovation Management (Feb. 2008) study of lead users of children’s computer games, Exercise 12.13 (p. 628). Recall that the researchers modeled lead-user rating (y, measured on a 5-point scale) as a function of gender (x1 = 1 if female, 0 if male), age ( x2, years), degree of centrality ( x3, measured as the number of direct ties to other peers in the network), and betweenness centrality ( x4, measured as the number of shortest paths between peers). The least squares prediction equation was   = 3.58 + .01x1 - .06x2 - .01x3 + .42x4

a. Compute the predicted lead-user rating of a 10-yearold female child with 5 direct ties to other peers in her social network and with 2 shortest paths between peers.

b. Compute an estimate for the mean lead-user rating of all 8-year-old male children with 10 direct ties to other peers and with 4 shortest paths between peers.

Exercise 12.13

Characteristics of lead users. During new product development, companies often involve “lead users,” i.e., creative individuals who are on the leading edge of an important market trend. Creativity and Innovation Management (Feb. 2008) published an article on identifying the social network characteristics of lead users of children’s computer games. Data were collected for n = 326 children and the following variables measured: lead-user rating (y, measured on a 5-point scale), gender (x1 = 1 if female, 0 if male), age (x2, years), degree of centrality (x3 , measured as the number of direct ties to other peers in the network), and between ness centrality (x4 , measured as the number of shortest paths between peers). A first-order model for y was fit to the data, yielding the following least squares prediction equation:

a. Give two properties of the errors of prediction that result from using the method of least squares to obtain the parameter estimates.

b. Give a practical interpretation of the estimate of β4 in the model.

c. A test of H0: β4= 0 resulted in a p -value of .002. Make the appropriate conclusion at a = .05.

 

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Maurice Tutor
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Status NEW Posted 17 Feb 2018 08:02 PM My Price 9.00

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