Maurice Tutor

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Teaching Since: May 2017
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Education

  • MCS,PHD
    Argosy University/ Phoniex University/
    Nov-2005 - Oct-2011

Experience

  • Professor
    Phoniex University
    Oct-2001 - Nov-2016

Category > Management Posted 04 Mar 2018 My Price 6.00

elements of the third row

2.5  Let z = magic(5).                   1

 

a. Perform the following operations to z in the order given: i. Divide column 2 by 3.

 

         Add the elements of the third row to the elements in the fifth row (the third row remains unchanged).

 

           Multiply the elements of the first column by the corresponding elements of the fourth column and place the result in the first column.

 

          Set the diagonal elements to 2.

 

         If the result obtained in (a) (iv) is denoted q, then obtain the diagonal of qqœ (Answer: [486 104189 7300 44522 111024]œ).

         Determine the maximum and minimum values of q.

 

            Let w = magic(2) and w' be the transpose of w.

 

a.  Using repmat create the following (4 * 4) matrix

cw

w d

w

w

 

b.  Using repmat create the following (6 * 2) matrix

 

J w K w

w

 

         Use repmat and the column augmentation procedure to create the following (6 * 4) matrix:

 

w

w¿

K

J ww

ww¿¿

 

         Repeat (a), (b), and (c) without using repmat, that is, using only column and row augmentation procedures.


        

         P = 100P /P %

         o

         T

         where PT is the total nondimensional power in the signal

 

 

 

            Let x = magic(3). Using element swapping technique of Example 2.3

 

         Create a new matrix in which each row of x has been moved up by one row and the first row becomes the last row.

 

         Create a new matrix in which each column of x has been moved to the right and the last column becomes the first column.

 

            Manipulate the output of magic(5) to produce the following altered matrix:

 

 

17

24

1

8

15

 

 

 

17

24

1

8

0

 

 

23

5

7

14

16

 

:

 

23

5

7

0

16

 

magic(5) =

4

6

13

20

22

 

 

4

6

0

20

22

 

E

10

12

19

21

3

U

 

E

10

0

19

21

3

U

11

18

25

2

9

 

0

18

25

2

9

Section 2.5

Answers

Maurice Tutor
(5)
Status NEW Posted 04 Mar 2018 06:03 PM My Price 6.00

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