Alpha Geek

(8)

$10/per page/Negotiable

About Alpha Geek

Levels Tought:
University

Expertise:
Accounting,Algebra See all
Accounting,Algebra,Architecture and Design,Art & Design,Biology,Business & Finance,Calculus,Chemistry,Communications,Computer Science,Environmental science,Essay writing,Programming,Social Science,Statistics Hide all
Teaching Since: Apr 2017
Last Sign in: 438 Weeks Ago, 1 Day Ago
Questions Answered: 9562
Tutorials Posted: 9559

Education

  • bachelor in business administration
    Polytechnic State University Sanluis
    Jan-2006 - Nov-2010

  • CPA
    Polytechnic State University
    Jan-2012 - Nov-2016

Experience

  • Professor
    Harvard Square Academy (HS2)
    Mar-2012 - Present

Category > Statistics Posted 25 May 2017 My Price 3.00

Compute the probability of exactly one accident during a month

 

Compute the probability of exactly one accident during a month
 
 

Answers

Alpha Geek
(8)
Status NEW Posted 25 May 2017 12:05 PM My Price 3.00

-----------

Attachments

file 1495716163-Answer.docx preview (36 words )
C-----------omp-----------ute----------- th-----------e p-----------rob-----------abi-----------lit-----------y o-----------f e-----------xac-----------tly----------- on-----------e a-----------cci-----------den-----------t d-----------uri-----------ng -----------a m-----------ont-----------h -----------May----------- 31----------- 20-----------15 -----------04:-----------22 -----------PM ----------- An-----------swe-----------r -----------Ave-----------rag-----------e o-----------f 1-----------5 a-----------irc-----------raf-----------t a-----------cci-----------den-----------ts -----------occ-----------ur -----------eac-----------h y-----------ear-----------. b-----------. X-----------~Po-----------iss-----------on(-----------?=1-----------5/1-----------2=1-----------.25----------- pe-----------r m-----------ont-----------h) -----------P(X-----------=x)-----------=(1-----------.25-----------^x)-----------*ex-----------p(------------1.2-----------5)/-----------x! -----------So -----------the----------- pr-----------oba-----------bil-----------ity----------- is----------- P(-----------X=0-----------)=(-----------1.2-----------5^0-----------)*e-----------xp(------------1.-----------25)-----------/1=----------- 0.-----------286-----------504-----------8 X-----------~Po-----------iss-----------on(-----------?=1-----------5/1-----------2=1-----------.25----------- pe-----------r m-----------ont-----------h) -----------P(X-----------=x)-----------=(1-----------.25-----------^x)-----------*ex-----------p(------------1 -----------
Not Rated(0)