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Category > Engineering Posted 27 May 2017 My Price 8.00

Draw an equilibrium band diagram for this junction

 

1. An abrupt Si p-n junction has the following properties at 300K:

p-side n-side units

 

 

 

 

Draw an equilibrium band diagram for this junction, including numerical values for the Fermi level position relative to the intrinsic level on each side of the junction. Find the contact potential from the diagram and compare with the analytical expression for.

 
 

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Status NEW Posted 27 May 2017 01:05 PM My Price 8.00

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file 1495890076-1549316_1_636313911323248140_edc.docx preview (215 words )
A-----------n a-----------bru-----------pt -----------Si -----------p-n----------- ju-----------nct-----------ion----------- ha-----------s t-----------he -----------fol-----------low-----------ing----------- pr-----------ope-----------rti-----------es -----------at -----------300----------- o-----------K: ----------- Pr-----------ope-----------rty----------- P -----------sid-----------e N----------- si-----------de -----------Uni-----------t -----------Dop-----------ing----------- NA----------- =----------- 10-----------18 -----------NDÂ----------- = -----------5X1-----------015----------- cm------------3 ----------- Li-----------fet-----------ime----------- tn----------- =----------- 0.-----------1 t-----------p -----------= 1-----------0 u-----------SMo-----------bil-----------ity----------- un----------- =----------- 25-----------0 u-----------n -----------= 1-----------300----------- cm-----------2/V------------s ----------- Mo-----------bil-----------ity----------- up----------- =----------- 10-----------0 u-----------p -----------= 4-----------00 -----------cm2-----------/V------------s ----------- ----------- ----------- ----------- A----------- = -----------10------------4 -----------cm------------2 ----------- ----------- ----------- ----------- ----------- ----------- -----------VT ----------- = -----------25m-----------v ----------- ----------- ----------- ----------- ----------- ----------- n-----------i -----------= 1-----------.5X-----------101-----------0 -----------cm------------3 -----------Vn -----------= E-----------f ------------ Ei----------- = -----------Vt*-----------ln[-----------Nd/-----------ni]----------- = -----------0.3-----------3 -----------Vp -----------= E-----------i ------------ Ef----------- = -----------Vt*-----------ln[-----------Na/-----------ni]----------- = -----------0.4-----------6 V----------- V-----------bi -----------= V-----------n +----------- Vp----------- = -----------0.7-----------93V----------- 1-----------371-----------600-----------550-----------545-----------
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