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Category > Applied Sciences Posted 29 May 2017 My Price 4.00

Determine the work and heat transfer for the process

 

Five kilograms of water, initially a saturated vapor at 100 kPa, are cooled to saturated liquid while the pressure is maintained constant. Determine the work and heat transfer for the process, each in kJ. Show that the heat transfer equals the change in enthalpy of the water in this case.

 

 

 
 

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Status NEW Posted 29 May 2017 06:05 AM My Price 4.00

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file 1496041316-Answer.docx preview (147 words )
F-----------ive----------- ki-----------log-----------ram-----------s o-----------f w-----------ate-----------r, -----------ini-----------tia-----------lly----------- a -----------sat-----------ura-----------ted----------- va-----------por----------- at----------- 10-----------0 k-----------Pa,----------- ar-----------e c-----------ool-----------ed -----------to -----------sat-----------ura-----------ted----------- li-----------qui-----------d w-----------hil-----------e t-----------he -----------pre-----------ssu-----------re -----------is -----------mai-----------nta-----------ine-----------d c-----------ons-----------tan-----------t. -----------Det-----------erm-----------ine----------- th-----------e w-----------ork----------- an-----------d h-----------eat----------- tr-----------ans-----------fer----------- fo-----------r t-----------he -----------pro-----------ces-----------s, -----------eac-----------h i-----------n k-----------J. -----------Sho-----------w t-----------hat----------- th-----------e h-----------eat----------- tr-----------ans-----------fer----------- eq-----------ual-----------s t-----------he -----------cha-----------nge----------- in----------- en-----------tha-----------lpy----------- of----------- th-----------e w-----------ate-----------r i-----------n t-----------his----------- ca-----------se.----------- Â-----------  -----------Oct----------- 08----------- 20-----------16 -----------03:-----------37 -----------PM ----------- An-----------swe-----------r: ----------- M-----------ass-----------, m----------- = -----------5 k-----------g P-----------res-----------sur-----------e, -----------P =----------- 10-----------0 k-----------Pa -----------= 1----------- ba----------- So-----------lut-----------ion-----------: L-----------ate-----------nt -----------hea-----------t o-----------f v-----------apo-----------ris-----------ati-----------on -----------of -----------wat-----------er -----------L =----------- 22-----------60 -----------kJ/-----------kg
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