Two parallel PEC plates, each having a total surface area of 2 cm2
Two parallel PEC plates, each having a total surface area of 2 cm2, form a parallel plate capacitor. The separation between the PEC plates is 1.25 mm and the medium between the plates is initially free space. A 100- Volt battery is attached to the plates, charges them, and is then removed. After removal of the battery, a 1 mm thick dielectric slab, with a dielectric constant (relative permittivity) of 5 and an area of 2 cm2Â on each of its sides is inserted between the PEC plates and occupies the lower part of the space between the PEC plates (basically touching the lower PEC plate), as shown in the figure below. After insertion of the dielectric slab, find the:
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(a) Total charge Q on the lower and upper PEC plates (in C).
(b) Surface charge density on the upper and lower PEC plates (in C/m2).
(c) Electric flux density in the:
1. Dielectric (in C/m2)
2. Free space medium (in C/m2)
(d) Electric field intensity in the:
1. Dielectric (in V/m)
2. Free space medium (in V/m)
(e) Total voltage in the:
1. Dielectric slab (in V)
2. Free-space medium (in V)
3. Between the PEC plates (dielectric slab + free space medium) (in V)
(f) The capacitance across the:
1. Dielectric slab (in farads)
2. Free-space medium (in farads)
3. Between the PEC plates (dielectric slab + free space medium) (in farads)
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Posted 02 Jun 2017 10:06 AM
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file 1496399077-1752920_1_636319155406042344_Q1parellelplate-capacitor.docx preview (460 words )
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