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Category > Engineering Posted 27 Apr 2017 My Price 2.00

In methane combustion

In methane combustion, the following reaction pair is important;

 

At 1500K, the equilibrium constant Kp has a value of 0.003691 based on a reference-state pressure of 1 atm (101,325 Pa). Derive an algebraic expression for the forward rate coefficient kf. Evaluate your expression for a temperature of 1500K. Give units. 

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Status NEW Posted 27 Apr 2017 05:04 PM My Price 2.00

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file 1493314171-Answer.docx preview (70 words )
I-----------n m-----------eth-----------ane----------- co-----------mbu-----------sti-----------on,----------- th-----------e f-----------oll-----------owi-----------ng -----------rea-----------cti-----------on -----------pai-----------r i-----------s i-----------mpo-----------rta-----------nt;----------- ----------- At----------- 15-----------00K-----------, t-----------he -----------equ-----------ili-----------bri-----------um -----------con-----------sta-----------nt -----------KpÂ----------- ha-----------s a----------- va-----------lue----------- of----------- 0.-----------003-----------691----------- ba-----------sed----------- on----------- a -----------ref-----------ere-----------nce------------st-----------ate----------- pr-----------ess-----------ure----------- of----------- 1 -----------atm----------- (1-----------01,-----------325----------- Pa-----------). -----------Der-----------ive----------- an----------- al-----------geb-----------rai-----------c e-----------xpr-----------ess-----------ion----------- fo-----------r t-----------he -----------for-----------war-----------d r-----------ate----------- co-----------eff-----------ici-----------ent----------- kf-----------. E-----------val-----------uat-----------e y-----------our----------- ex-----------pre-----------ssi-----------on -----------for----------- a -----------tem-----------per-----------atu-----------re -----------of -----------150-----------0K.----------- Gi-----------ve -----------uni-----------ts.-----------  ----------- An-----------swe-----------r -----------Kr -----------= 1-----------.82-----------*10-----------^5 -----------e^(------------98-----------35/-----------T) -----------m^6-----------/mo-----------l^2-----------s a-----------t T----------- = -----------150-----------0 K----------- -----------Kr -----------= 1-----------.82-----------*10-----------^5 -----------e^(------------98-----------35/-----------150-----------0) -----------m^6-----------/mo-----------l^2-----------s =-----------
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