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Category > Math Posted 06 Jun 2017 My Price 2.00

A skier of mass m descends a -degree hill at a constant speed

A skier of mass m descends a -degree hill at a constant speed. When Newton’s Laws are applied to the situation, the following system of equations is produced.

where g is the acceleration due to gravity, FN is the normal force exerted on the skier, and µk is the coefficient of friction. Use the system to define µk as a function of θ.

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Status NEW Posted 06 Jun 2017 06:06 PM My Price 2.00

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file 1496774680-2070553_1_636322715216377544_Friction.docx preview (21 words )
T-----------he -----------giv-----------en -----------equ-----------ati-----------ons----------- ar-----------e ----------- FN------------mg-----------cos-----------θ=-----------0â€-----------¦â€-----------¦â€-----------¦â€-----------¦â€-----------¦â€-----------¦â€-----------¦â€-----------¦eq-----------uat-----------ion----------- 1 ----------- mg-----------sin-----------θ------------µk-----------FN=-----------0â€-----------¦â€-----------¦â€-----------¦â€-----------¦â€-----------¦â€-----------¦â€-----------¦eq-----------uat-----------ion----------- 2 ----------- Fr-----------om -----------equ-----------ati-----------on -----------1 w-----------e g-----------et -----------FN=----------- mg-----------cos-----------θ ----------- Su-----------bst-----------itu-----------tin-----------g i-----------n e-----------qua-----------tio-----------n 2----------- we----------- ge-----------t, ----------- µ-----------kFN-----------= m-----------gsi-----------nθ----------- Â-----------µk -----------mgc-----------osÎ-----------¸= -----------mgs-----------inÎ-----------¸ -----------µk-----------=ta-----------nθ----------- -----------
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