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Category > Engineering Posted 13 Jun 2017 My Price 5.00

The stream from a gas well is a mixture containing 50-mol-% methane

The stream from a gas well is a mixture containing 50-mol-% methane, 10-mol-% ethane, 20-mol-% propane, and 20-mol-% n-butane. This stream is fed into a partial condenser maintained at a pressure of 17.24 bar, where its temperature is brought to 300.15 K (27°C). Determine the molar fraction of the gas that condenses and the compositions of the liquid and vapor phases leaving the condenser.

 

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Alpha Geek
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Status NEW Posted 13 Jun 2017 06:06 AM My Price 5.00

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file 1497336390-Answer.docx preview (166 words )
A-----------nsw-----------er ----------- ba-----------sis----------- -1-----------00 -----------mol----------- ga-----------s m-----------ixt-----------ue ------------ m-----------ole----------- fr-----------act-----------ion----------- - -----------1 m-----------ole----------- me-----------ths-----------ne ------------ C-----------H4 ------------ 5-----------0 m-----------ole-----------s ------------ 0.-----------5 E-----------THA-----------NE ------------C2-----------H6 ------------ 1-----------0 m-----------ole-----------s ------------ 0.-----------1 p-----------rop-----------ane----------- - -----------C3H-----------8 ------------ 20----------- mo-----------les----------- - -----------0.2----------- n ------------bu-----------tan-----------e ------------ C4-----------H10----------- - -----------20 -----------mol-----------es ------------=0-----------.2 -----------ave-----------rag-----------e m-----------ol.-----------wt -----------of -----------gas----------- mi-----------xtu-----------re -----------= 0-----------.5 -----------*16----------- + -----------0.1-----------*30----------- + -----------0.2----------- *4-----------4 +----------- 0.-----------2 *----------- 58----------- = -----------8 +----------- 3 -----------+ 8-----------.8 -----------+11-----------.6 -----------=31----------- .4----------- g -----------/mo-----------l P----------- = -----------17.-----------24 -----------bar----------- ,T----------- =3-----------00 -----------oc -----------,t -----------=27----------- oc----------- R -----------= 0-----------.08-----------314----------- n=----------- P.-----------V /-----------RT -----------NOW----------- V1----------- /V-----------2 =----------- T1-----------/T2----------- 22-----------.4 -----------/V2----------- = -----------273-----------.15----------- / -----------300----------- 22-----------.4 -----------*30-----------0 /-----------273-----------.15----------- = -----------V2 -----------= 2-----------4.6----------- Li-----------ter-----------s
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