A 208-V, two-pole, 60-Hz, Y-connected wound-rotor
7-7. A 208-V, two-pole, 60-Hz, Y-connected wound-rotor induction motor is rated at 15 hp. Its equivalent circuit components are
 R1  = 0.200 0
x, = 0.410 0
Pmecb = 250 W
R2 = 0.120 0 Â Â Â Â Â Â Â Â Â Â Â Â Â
X2 = 0.410 0
Pmisc = 0 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Pcae = 180 W
For a slip of 0.05, find
(a) Â The line current h
(b) Â The stator copper losses PscL
(c) Â The air-gap power PAo
(d)  The power  converted  from electrical  to mechanical  form Pcoov
( e) Â The induced torque -rind
(j) Â The load torque T1oad
(g) Â The overall machine efficiency
(h) Â The motor speed in revolutions per minute and radians per second
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Answers
Status NEW
Posted 01 May 2017 04:05 PM
My Price 7.00
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