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Category > Applied Sciences Posted 19 Jun 2017 My Price 5.00

For the beam and loading shown, (a) draw the shear and bending-moment diagrams

Using the method of Sec. 7.6, solve Prob. 7.34.

Prob. 7.34. For the beam and loading shown, (a) draw the shear and bending-moment diagrams, (b) determine the maximum absolute values of the shear and bending moment.

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Status NEW Posted 19 Jun 2017 10:06 AM My Price 5.00

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Attachments

file 1497869753-1586756_1_636333754479025860_simply-supported-beam.xlsx preview (44 words )
Si-----------mpl-----------y s-----------upo-----------rte-----------d b-----------eam----------- wi-----------th -----------ben-----------din-----------g m-----------ome-----------nt -----------at -----------poi-----------nt -----------BRe-----------ati-----------on -----------at -----------A a-----------nd -----------CTa-----------ke -----------mom-----------ent----------- ab-----------out----------- CR-----------A*L-----------+Mo-----------=0R-----------A=M-----------o/L-----------Tak-----------ing----------- mo-----------men-----------t a-----------bou-----------t A-----------RC*-----------L+M-----------o=0-----------RC=-----------Mo/-----------LBe-----------ndi-----------ng -----------Mom-----------ent----------- at----------- A`-----------=0B-----------end-----------ing----------- mo-----------men-----------t a-----------t l-----------eft----------- of----------- po-----------int----------- B`-----------=Mo-----------/L*-----------L/2-----------`=M-----------o/2-----------Ben-----------din-----------g m-----------ome-----------nt -----------at -----------rig-----------ht -----------of -----------poi-----------nt -----------B`=------------Mo-----------/L*-----------L/2-----------`=------------Mo/-----------2Be-----------ndi-----------ng -----------Mom-----------ent----------- at----------- CM-----------axi-----------mum----------- sh-----------are----------- fo-----------rce----------- = -----------Mo/-----------LMa-----------xim-----------um -----------ben-----------din-----------g m-----------ome-----------nt=----------- Mo-----------/2 -----------
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