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Category > Statistics Posted 19 Jun 2017 My Price 3.00

City Planning

City Planning There are six women and seven men on a committee for city services improvement. A subcommittee of five members is being selected at random to study the feasibility of modernizing the water treatment facility. What is the probability that the committee will have at least three women?

 

 

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Alpha Geek
(8)
Status NEW Posted 19 Jun 2017 12:06 PM My Price 3.00

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file 1497874260-2073423_1_636331858635419980_Proabability-latest.docx preview (68 words )
T-----------her-----------e a-----------re -----------six----------- wo-----------men----------- an-----------d s-----------eve-----------n m-----------en -----------on -----------a c-----------omm-----------itt-----------ee -----------for----------- ci-----------ty -----------ser-----------vic-----------es -----------imp-----------rov-----------eme-----------nt.----------- A -----------sub-----------com-----------mit-----------tee----------- of----------- fi-----------ve -----------mem-----------ber-----------s i-----------s b-----------ein-----------g s-----------ele-----------cte-----------d a-----------t r-----------and-----------om -----------to -----------stu-----------dy -----------the----------- fe-----------asi-----------bil-----------ity----------- of----------- mo-----------der-----------niz-----------ing----------- th-----------e w-----------ate-----------r t-----------rea-----------tme-----------nt -----------fac-----------ili-----------ty.----------- P-----------rob-----------abi-----------lit-----------y o-----------f h-----------avi-----------ng -----------3 w-----------ome-----------n=(-----------C63-----------*C7-----------2)/-----------(C5-----------13)-----------=(2-----------0*2-----------1)/-----------(12-----------87)-----------=0.-----------326-----------34 ----------- Pr-----------oba-----------bil-----------ity----------- of----------- ha-----------vin-----------g 4----------- wo-----------men-----------=(C-----------64*-----------C71-----------)/(-----------C51-----------3)=-----------(15-----------*7)-----------/(1-----------287-----------)= -----------0.0-----------815-----------85 ----------- Pr-----------oba-----------bil-----------ity----------- of----------- ha-----------vin-----------g 5----------- wo-----------men-----------=(C-----------65*-----------C70-----------)/(-----------C51-----------3)=-----------(6*-----------1)/-----------(12-----------87)-----------= 0-----------.00-----------466-----------2 -----------Pro-----------bab-----------ili-----------ty
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