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Category > Applied Sciences Posted 20 Jun 2017 My Price 5.00

Find the first three iterates of the function f(z) = 0.5z + (4 - 2i) for each initial value.

Find the first three iterates of the function f(z) = 0.5z + (4 - 2i) for each initial value.

 

 

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Alpha Geek
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Status NEW Posted 20 Jun 2017 08:06 AM My Price 5.00

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file 1497948273-2073306_1_636334461418958354_Complex-iterates.docx preview (121 words )
W-----------e h-----------ave----------- f(-----------z)=-----------0.5-----------z+(-----------4-2-----------i) ----------- 47-----------.z0-----------=4i----------- ----------- ----------- Th-----------e f-----------irs-----------t i-----------ter-----------ate----------- z1-----------=(0-----------.5)-----------(4i-----------)+ -----------(4------------2i)-----------=2i-----------+(4------------2i-----------)=4----------- ----------- ----------- Th-----------e s-----------eco-----------nd -----------ite-----------rat-----------e z-----------2=0-----------.5(-----------4)+----------- (4------------2i-----------)=2-----------+(4------------2i-----------)=6------------2i----------- ----------- ----------- T-----------he -----------thi-----------rd -----------ite-----------rat-----------e z-----------3=(-----------0.5-----------)( -----------6-2-----------i)+-----------(4------------2i)-----------=3------------i+(-----------4-2-----------i)=-----------7-3-----------i -----------48.-----------z0=------------8 ----------- ----------- ----------- Th-----------e f-----------irs-----------t i-----------ter-----------ate----------- z1-----------=0.-----------5(------------8)+----------- (4------------2i-----------)=------------4+(-----------4-2-----------i)=------------2i----------- ----------- ----------- T-----------he -----------sec-----------ond----------- it-----------era-----------te -----------z2=-----------0.5-----------(-2-----------i)+----------- (4------------2i-----------)=------------i+(-----------4-2-----------i)=-----------4-3-----------i ----------- ----------- -----------The----------- th-----------ird----------- it-----------era-----------te -----------z3=-----------0.5-----------(4------------3i)-----------+ (-----------4-2-----------i)=-----------2-1-----------.5i-----------+(4------------2i-----------)=6------------3.-----------5i ----------- 49-----------.z0-----------=-4-----------+6i----------- ----------- ----------- Th-----------e f-----------irs-----------t
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