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Category > Applied Sciences Posted 20 Jun 2017 My Price 3.00

Find the charge on the capacitor in an LRC-series circuit

Find the charge on the capacitor in an LRC-series circuit at t = 0.01 s when L = 0.05 h, R = 2 Ω, C = 0.01 f, E(t) = 0 V, q(0) = 5 C, and i(0) = 0 A. Determine the first time at which the charge on the capacitor is equal to zero.

 

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Alpha Geek
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Status NEW Posted 20 Jun 2017 09:06 AM My Price 3.00

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file 1497950246-Answer.docx preview (113 words )
A-----------nsw-----------er ----------- Lq-----------&qu-----------ot;----------- + -----------Rq'----------- + -----------q/C----------- = -----------E(t-----------) L----------- = -----------0.0-----------5 =----------- 1/-----------20 -----------(1/-----------20)-----------q&q-----------uot-----------; +----------- 2q-----------' +----------- 10-----------0q -----------= 0----------- =&-----------amp-----------;gt-----------; q-----------&qu-----------ot;----------- + -----------40q-----------' +-----------200-----------0q -----------= 0----------- m^-----------2 +----------- 40-----------m +----------- 20-----------00 -----------= 0----------- //----------- Th-----------is -----------is -----------the----------- au-----------xil-----------iar-----------y e-----------qua-----------tio-----------n m----------- = ------------20----------- +/------------ 4-----------0i -----------// -----------Aft-----------er -----------app-----------lyi-----------ng -----------the----------- qu-----------adr-----------ati-----------c f-----------orm-----------ula----------- q(-----------t) -----------= A-----------(e^------------20-----------t)c-----------os(-----------40t-----------) +----------- B(-----------e^------------20t-----------)si-----------n(4-----------0t)----------- //----------- wh-----------ere----------- A -----------and----------- B -----------are----------- co-----------nst-----------ant-----------s q-----------(0)----------- = -----------5 =----------- A -----------=&a-----------mp;-----------gt;----------- A -----------= 5----------- q'-----------(t)----------- = ------------20-----------A(e-----------^-2-----------0t)-----------*co-----------s(4-----------0t)----------- - -----------40A-----------(e^------------20-----------t)*-----------sin-----------(40-----------t) -----------_ 4-----------0B(-----------e^------------20t-----------)*c-----------os(-----------40t-----------) ------------ 20-----------B(e-----------^-2-----------0t)-----------*si-----------n(4-----------0t)-----------
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