Maurice Tutor

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Teaching Since: May 2017
Last Sign in: 398 Weeks Ago, 6 Days Ago
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Education

  • MCS,PHD
    Argosy University/ Phoniex University/
    Nov-2005 - Oct-2011

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  • Professor
    Phoniex University
    Oct-2001 - Nov-2016

Category > Computer Science Posted 21 Jul 2017 My Price 3.00

demonstrate that for CMAC

In this problem, we demonstrate that for CMAC, a variant that XORs the second key after applying the final encryption doesn’t work. Let us consider this for the case of the message being an integer multiple of the block size. Then, the variant can be expressed as VMAC(K, M) = CBC(K, M)  width=K1 Now suppose an adversary is able to ask for the MACs of three messages: the message0 = 0n where is the cipher block size; the message 1 = 1n ; and the message 1 || 0. As a result of these three queries, the adversary gets T0 = CBC(K, 0)  width= K1; T1 = CBC(K, 1)  width= K1 and T2 = CBC(K, [CBC(K, 1)])  width= K1 . Show that the adversary can compute the correct MAC for the (unqueried) message0 || (T0  width=T1)

Answers

Maurice Tutor
(5)
Status NEW Posted 21 Jul 2017 08:07 AM My Price 3.00

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