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Category > Applied Sciences Posted 28 Jul 2017 My Price 6.00

Determine the maximum applicable shear force on the member (a)

The two cross sections shown below, (a) and (b), are subjected to a vertical shear force as shown. The members are fastened by nails that can support a load of 25.00kN each and are spaced perpendicularly to the page in increments of s = 125.0mm . The geometries of the cross sections are given by a= 225.0mm , b = 50.00mm , c = 280.0mm , d = 125mm , and e = 330mm . Assume the cross sections are uniform along the entire lengths of the members.

Determine the maximum applicable shear force on the member (a).

Determine the maximum applicable shear force on the member (b).

Determine the required spacing in the weaker member such that both cross sections can support the same maximum applicable shear force as defined by the stronger member.

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Alpha Geek
(8)
Status NEW Posted 28 Jul 2017 09:07 AM My Price 6.00

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Attachments

file 1501233534-1204439_1_636367707003279297_The-two-cross-sections.docx preview (55 words )
----------- We----------- kn-----------ow,----------- ----------- As----------- pe-----------r T-----------he -----------Que-----------sti-----------on -----------in -----------the----------- Fi-----------g A-----------, -----------P =----------- 25----------- Kn----------- a----------- = ----------- 22-----------5 m-----------m -----------b= -----------50 -----------mm ----------- c -----------= 2-----------80 -----------mm ----------- Ef-----------fec-----------tiv-----------e S-----------pan----------- fo-----------r t-----------he -----------Bea-----------m =----------- (2-----------25------------50*-----------2) -----------= 1-----------25 -----------mm ----------- Co-----------nsi-----------der-----------ing----------- th-----------e f-----------orc-----------e a-----------cti-----------on -----------in -----------the----------- mi-----------ddl-----------e P-----------ort-----------ion----------- of----------- th-----------e b-----------eam----------- , ----------- V1----------- = -----------(25----------- *(-----------125-----------/2)-----------^2*-----------( (-----------3*6-----------2.5-----------)+6-----------2.5-----------))/-----------125-----------^3 -----------= 1-----------2.5----------- Kn----------- T-----------hen----------- Sh-----------ear----------- Fo-----------rce----------- wi-----------ll -----------be ----------- 12-----------.5 -----------Kn ----------- -----------
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