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Category > Physics Posted 28 Jul 2017 My Price 3.00

An inductor of the form of Fig. 1.24 has dimensions

An inductor of the form of Fig. 1.24 has dimensions: Cross-sectional area Ac = 3.6 cm2 Mean core length lc = 15 cm N = 75 turns Assuming a core permeability of µ = 2100/~0 and neglecting the effects of leakage flux and fringing fields, calculate the air-gap length required to achieve an inductance of 6.0 mH.

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Status NEW Posted 28 Jul 2017 12:07 PM My Price 3.00

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