Alpha Geek

(8)

$10/per page/Negotiable

About Alpha Geek

Levels Tought:
University

Expertise:
Accounting,Algebra See all
Accounting,Algebra,Architecture and Design,Art & Design,Biology,Business & Finance,Calculus,Chemistry,Communications,Computer Science,Environmental science,Essay writing,Programming,Social Science,Statistics Hide all
Teaching Since: Apr 2017
Last Sign in: 345 Weeks Ago, 2 Days Ago
Questions Answered: 9562
Tutorials Posted: 9559

Education

  • bachelor in business administration
    Polytechnic State University Sanluis
    Jan-2006 - Nov-2010

  • CPA
    Polytechnic State University
    Jan-2012 - Nov-2016

Experience

  • Professor
    Harvard Square Academy (HS2)
    Mar-2012 - Present

Category > Statistics Posted 02 Aug 2017 My Price 5.00

to determine the probability that a certain component lasts more than 350 hours

to determine the probability that a certain component lasts more than 350 hours in operation, a random sample of 37 components was tested. Of these, 24 lasted longer than 350 hours.

(a) Construct a 95% CI for the probability, p, that a randomly selected component lasts more than 350 hours.

(b) A system consists of two such components connected in series. Thus, the system operates if and only if both components operate properly. Construct a 95% CI for the probability that the system lasts more than 350 hours. You can assume that the life spans of the two components in the system are independent. (Hint. Express the probability that the system lasts more than 350 hours in terms of p.)

 

Answers

Alpha Geek
(8)
Status NEW Posted 02 Aug 2017 10:08 AM My Price 5.00

n =----------- 37----------- an-----------d p----------- = -----------pro-----------por-----------tio-----------n t-----------hat----------- la-----------ste-----------d l-----------ong-----------er -----------tha-----------n 3-----------50 -----------hou-----------rs -----------= 2-----------4/3-----------7 =----------- 0.-----------648-----------6 S-----------td -----------err-----------or -----------= r-----------t p-----------(1------------p)/-----------n =----------- 0.-----------078-----------4 M-----------arg-----------in -----------of -----------err-----------or -----------for----------- 95-----------% =----------- 1.-----------96*-----------std----------- er-----------ror-----------

Not Rated(0)